POLYCET,TGRJC MATHS PREVIOUS MCQ TEST-5

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• Choose one option from the given 4 alternative options.
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• After attempting all the questions, click the Submit button.
• Correct answers will be shown in green color.
• Wrong answers will be shown in red color.
• Your score will be displayed after submission.
• Every correct answer gives 1 mark.
• Every wrong answer deducts 1/4 mark from your total score.

1/10

Two dice are thrown simultaneously. Then the probability of getting the sum of the two numbers appeared on them is a prime number is

1)\(\frac{10}{36}\)

2)\(\frac{12}{36}\)

3)\(\frac{14}{36}\)

4)\(\frac{15}{36}\)

2/10

A bag contains 12 balls, out of them 'x' are white. If 6 more white balls are added to the bag, the probability of drawing a white ball will be doubled. Then x =

1)3

2)6

3)9

4)4

3/10

A number 'x' is selected from the number 1, 2, 3 and then a second number 'y' is randomly selected from the numbers 1, 4, 9. Then the probability, that the product of the two numbers (x and y) will be less than 9 is

1)\(\frac{4}{9} \)

2)\(\frac{5}{9} \)

3)\(\frac{7}{9} \)

4)\(\frac{3}{9} \)

4/10

The angle of elevation of the top of a hill at the foot of a tower is 60° and the angle of elevation of the top of the tower from the foot of the hill is 30°. If the tower is 50 m high, the height of the hill is..... metres.

1)100

2)\(50\sqrt{3}\)

3)150

4)\(150\sqrt{3}\)

5/10

The shadow of a pole standing on a even level ground is found to be 40 m longer, when Sun's attitude is 30° than when it was 60°. Then the height of the pole is..... metres.

1)\(20\sqrt{3}\)

2)\(30\sqrt{3}\)

3)\(40\sqrt{3}\)

4)\(10\sqrt{3}\)

6/10

An observer 1.5 m tall is 28.5 m away from a light pole. The angle of elevation of the top of the light pole from his eyes is 45°. Then the height of the light pole is..... metres.

1)28.5

2)27

3)31.5

4)30

7/10

The sum of all the odd integers between 2 and 100 divisible by 3 is.....

1)1683

2)867

3)1734

4)3366

8/10

The middle most term of the A.P. 7, 13, 19, ..., 247 is

1) \(a_{20}=121 \)

2) \(a_{21}=127 \)

3)\(a_{20}=127 \)

4)\(a_{21}=133 \)

9/10

If \(k^2+4k+8\),\(2k^2+3k+6\) and \(3k^2+4k+4\) are three consecutive terms of an A.P then k=

1)0

2)1

3)-1

4)3

10/10

If one root of \(4x^2 – 2x + (\lambda-4) = 0\) be the reciprocal of the other then λ = ....

1)4

2)-4

3)-8

4)2

Result: